In a human population, the frequencies of alleles A and a are 0.8 and 0.2, respectively. Assume gene A is autosomal and the population is under Hardy-Weinberg equilibrium. If five people are randomly selected, what is the probability that exactly 3 AA and 2 Aa individuals will be picked?I’ve worked out..AA=p^20.8^2=0.64Aa=2pq2x(0.8)(0.2)=0.32aa=q^20.2^2=0.04Just not sure about the probability of exactly 3 AA and 2 AaAlso another problemA population in Hardy-Weinberg equilibrium has eight times as many heterozygotes as homozygous recessives. What is the frequency of the dominant allele?